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On Sat, 2006-12-02 at 09:52 -0600, /dev/rob0 wrote:
> On Saturday 02 December 2006 05:25, Kevin Keane wrote:
> > 10.8.0.7 - broadcast address for the 10.8.0.4 network. All TCP/IP
> > networks always reserve the highest possible IP address in the
> > network for that purpose.
>
> Nit-pick: but it might not always be used for broadcast. For example,
> this mail is coming from my outbound relay, a host on a .55/29
> broadcast IP address. If there's no broadcast traffic (DHCP and NetBIOS
> use broadcasts) the broadcast IP can be used.
Really? I wasn't aware of that. In any case, I wouldn't recommend doing
that because I'd be rather doubtful that all TCP/IP implementations
would handle that properly. You might well have an ugly situation if you
are trying to send a packet to 10.0.8.255. Some embedded devices, such
as print servers, may well misinterpret it as broadcast anyway.
> > As you can see, each client will actually need four IP addresses with
> > this scheme. With a subnet mask of 255.255.255.0, you can squeeze in
> > 62 such subnets (10.8.0.0 and 10.8.0.252 are not valid as networks).
>
> Why not? I don't follow you here. Is it some quirk of OpenVPN?
No, it's one of the lesser known rules of subnetting. In fact, I didn't
even know about it until I tried to (mis)configure a Cisco router with
such a subnet and got an error message.
Actually - turns out that I was only half right. You actually CAN use
these subnets, but they used to be discouraged, and on older versions of
IOS you have to enable a special configuration
http://www.cisco.com/warp/public/105/40.html
In any case, this is actually off topic anyway.
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